Solution :
Suppose that the sequence {an} contains only finitely many composite numbers. That means that there exists N such that for all n > N an is odd.
Consider the
binary representation of an, n > N. The last digit of an
must be 1, which in turn implies that the fractional part of the binary
representation of has all its digits equal to 1 after N-th position. This
contradicts the irrationality of
.